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Invalid DN Syntax (34) Invalid DN Syntax解决办法

热度:928   发布时间:2016-04-24 12:40:47.0
Invalid DN Syntax (34) Invalid DN Syntax
往ldap中添加节点,出现一下错误(认证已成功):
Error: LDAPException: Invalid DN Syntax (34) Invalid DN Syntax
LDAPException: Server Message: invalid DN
LDAPException: Matched DN: 

import com.novell.ldap.*;  
import java.io.UnsupportedEncodingException;  
   
  public class LDAPAdd {  
  public static void main(String[] args) {  
  int ldapPort = LDAPConnection.DEFAULT_PORT;  
  int ldapVersion = LDAPConnection.LDAP_V3;  
  String ldapHost = "localhost";  
  String loginDN = "cn=Manager,dc=lily,dc=com";  
  String password = "lily";  
  LDAPConnection lc = new LDAPConnection();  
  String newUserName = "helin";
  try {  
  // connect to the server  
  lc.connect(ldapHost, ldapPort);  
  // authenticate to the server  
  lc.bind(ldapVersion, loginDN, password.getBytes("UTF8"));  
   
  //long start = System.currentTimeMillis();  
  LDAPAttributeSet attrSet = new LDAPAttributeSet();
  attrSet.add(new LDAPAttribute("objectclass","person"));
  attrSet.add(new LDAPAttribute("cn",newUserName));
  attrSet.add(new LDAPAttribute("sn",newUserName));
  LDAPEntry entry = new LDAPEntry("cn=" + newUserName + "dc=lily,dc=com",attrSet);
  lc.add(entry);
  System.out.println("ok");  
   
  //System.out.println(System.currentTimeMillis() - start);  
  //lc.add( newEntry );  
  //System.out.println( "\nAdded object: " + dn + " successfully." );  
   
  // disconnect with the server  
   
  lc.disconnect();
  }  
  catch (LDAPException e) {  
  System.out.println("Error: " + e.toString());  
  }  
  catch (UnsupportedEncodingException e) {  
  System.out.println("Error: " + e.toString());  
  }  
   
  System.exit(0);  
  }  
   
  }

------解决方案--------------------
看错误的样子是说:无效的DN语法,你在查查语法有没有什么问题
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