谁有这方面的资料,能不能提供一下~~
------解决方案--------------------
有LED的字体,直接使用这种字体显示比较方便。
------解决方案--------------------
- Java code
public class Test {
public static void main(String[] args) {
LED led = new LED();
char[][] chss = led.getLED("0123456789");
LED.print(chss);
}
}
class LED {
/**
* 每个 LED 的大小,可以进行调整
*/
public final static int ROW = 7;
public final static int COL = 7;
/**
* 每个 LED 的间隔
*/
private final static int SEPARATOR = 1;
private final static char FILL_CHAR = '#';
private final static char SPACE_CHAR = ' ';
/**
* 工具方法,用于输出 LED
* @param chs
*/
public static void print(char[][] chs) {
for (int i = 0; i < chs.length; i++) {
for (int j = 0; j < chs[i].length; j++) {
System.out.print(chs[i][j]);
}
System.out.println();
}
}
/**
* 根据数字得到 LED 显示数组
* @param num *
* @return
*/
public char[][] getLED(String num) {
char[] chs = num.toCharArray();
char[][][] chsss = new char[chs.length][][];
for (int i = 0; i < chs.length; i++) {
chsss[i] = showLed(chs[i] - '0');
}
return putManyLed(chsss);
}
/**
* 将多个 LED 组成一排
* @param chsss
* @return
*/
private char[][] putManyLed(char[][][] chsss) {
if (chsss.length < 1) {
throw new IllegalArgumentException("LED is NULL!");
}
if (chsss.length == 1) {
return chsss[0];
}
char[][] chss = new char[ROW][chsss.length * (COL + SEPARATOR)
- SEPARATOR];
for (int i = 0; i < chsss.length; i++) {
int m = i * (COL + SEPARATOR);
for (int j = 0; j < chsss[i].length; j++) {
for (int k = 0; k < chsss[i][j].length; k++) {
chss[j][m + k] = chsss[i][j][k];
}
}
}
for (int i = 0; i < chss.length; i++) {
for (int j = 0; j < chss[i].length; j++) {
if (chss[i][j] != FILL_CHAR) {
chss[i][j] = SPACE_CHAR;
}
}
}
return chss;
}
/**
*
* @param num
* @return
*/
private char[][] showLed(int num) {
boolean[] b = getLed(num);
char[][] chs = new char[ROW][COL];
if (b[0])
for (int i = 0; i < COL; i++)
chs[0][i] = FILL_CHAR;
if (b[1])
for (int i = 0; i <= ROW / 2; i++)
chs[i][COL - 1] = FILL_CHAR;
if (b[2])