譬如说在cmd下输入
java postfixCal 23+4-
会得到1?
------解决方案--------------------
- Java code
import java.util.LinkedList;import java.util.List;public class PostFix { public static void main(String[] args) { StringBuilder sb = new StringBuilder(); for(int i=0;i<args.length;i++) sb.append(args[i]+" "); System.out.println(calPostFix(sb.toString())); } private static double calPostFix(String str) { List<String> parts = new LinkedList<String>(); for(int i=0;i<str.length();) { if(str.charAt(i)==' ') { i++; continue; } int pos = i; while(Character.isDigit(str.charAt(i)) || str.charAt(i)=='.') //数字 i++; if(pos!=i) { parts.add(str.substring(pos, i)); continue; } //操作符 parts.add(str.charAt(i++)+""); } double nowValue = Double.parseDouble(parts.get(0)); return calPostFixParts(parts, 1, nowValue); } /**这里递归调用**/ private static double calPostFixParts(List<String> parts, int pos, double nowValue) { if(pos>=parts.size()) return nowValue; double res = cal(nowValue, parts.get(pos), parts.get(pos+1)); return calPostFixParts(parts, pos+2, res); } protected static double cal(double m, String b, String operator) { if(operator.length()!=1) throw new RuntimeException("操作符不合法"); Character op = operator.charAt(0); double n = Double.valueOf(b); switch(op) { case '+':return m+n; case '-':return m-n; case '*':return m*n; case '/':return m/n; case '^':return Math.pow(m, n); default:throw new RuntimeException("操作符不合法"); } }}