如:1-abc-w154e944
找到所有的连续数字,使之变长(例如6位,不足的前面补0)
执行结果:000001-abc-w000154e000944
用正则表达式实现
------解决方案--------------------
- Java code
Pattern pattern = Pattern.compile("(\\d+)"); Matcher matcher = pattern.matcher("1-abc-w154e944"); StringBuffer sbf = new StringBuffer(); while(matche.find()){ StringBuffer zero = new StringBuffer(); for(int i = (6 - matcher.group().length());i>0;i--){ zero.append("0"); } matcher.appendReplacement(sbf,zero+matcher.group()); } matcher.appendTail(sbf); System.out.println(sbf);
------解决方案--------------------
for example
- Java code
String str = "1-abc-w154e944";Pattern p = Pattern.compile("\\d+");Matcher m = p.matcher(str);StringBuffer buf = new StringBuffer();while (m.find()) { String s = String.format("000000%s", m.group()); m.appendReplacement(buf, s.substring(s.length()-6));}m.appendTail(buf);System.out.println(buf);