帮忙，把下面一段c++代码转为java代码，谢啦！
- C/C++ code
//笛卡尔坐标系typedef struct tagCRDCARTESIAN{double x;double y;double z;}CRDCARTESIAN,*PCRDCARTESIAN;//typedef CRDCARTESIAN *PCRDCARTESIAN;//大地坐标系typedef struct tagCRDGEODETIC{double longitude; //经度double latitude; //纬度 double height; //大地高,可设为0}CRDGEODETIC;typedef CRDGEODETIC *PCRDGEODETIC;void CoordCovert::GeodeticToCartesian (PCRDCARTESIAN pcc, PCRDGEODETIC pcg,double dSemiMajorAxis, double dFlattening){ double B; //纬度度数 double L; //经度度数 double L0; //中央经线度数 double l; //L-L0 double t; //tanB double m; //ltanB double N; //卯酉圈曲率半径 double q2; double x; //高斯平面纵坐标 double y; //高斯平面横坐标 double s; //赤道至纬度B的经线弧长 double f; //参考椭球体扁率 double e2; //椭球第一偏心率 double a; //参考椭球体长半轴 //double b; //参考椭球体短半轴 double a1; double a2; double a3; double a4; double b1; double b2; double b3; double b4; double c0; double c1; double c2; double c3; //投影带号 int zonewide=3; int Datum=84; //投影基准面类型：北京54基准面为54，西安80基准面为80，WGS84基准面为84 int prjno=0; // double IPI=0.0174532925199433333333; //3.1415926535898/180.0 B=pcg->latitude ; //纬度 L=pcg->longitude ; //经度 if (zonewide==6) { prjno=(int)(L/zonewide)+1; L0=prjno*zonewide-3; } else { prjno=(int)((L-1.5)/3)+1; L0=prjno*3; } if(Datum==54) { a=6378245; f=1/298.3; } else if(Datum==84) { a=6378137; f=1/298.257223563; } L0=L0*IPI; L=L*IPI; B=B*IPI; e2=2*f-f*f;//(a*a-b*b)/(a*a); l=L-L0; t=tan(B); m=l * cos(B); N=a/sqrt(1-e2* sin(B) * sin(B)); q2=e2/(1-e2)* cos(B)* cos(B); a1=1+(double)3/4*e2+(double)45/64*e2*e2+(double)175/256*e2*e2*e2+(double)11025/16384*e2*e2*e2*e2+(double)43659/65536*e2*e2*e2*e2*e2; a2=(double)3/4*e2+(double)15/16*e2*e2+(double)525/512*e2*e2*e2+(double)2205/2048*e2*e2*e2*e2+(double)72765/65536*e2*e2*e2*e2*e2; a3=(double)15/64*e2*e2+(double)105/256*e2*e2*e2+(double)2205/4096*e2*e2*e2*e2+(double)10359/16384*e2*e2*e2*e2*e2; a4=(double)35/512*e2*e2*e2+(double)315/2048*e2*e2*e2*e2+(double)31185/13072*e2*e2*e2*e2*e2; b1=a1*a*(1-e2); b2=(double)-1/2*a2*a*(1-e2); b3=(double)1/4*a3*a*(1-e2); b4=(double)-1/6*a4*a*(1-e2); c0=b1; c1=2*b2+4*b3+6*b4; c2=-(8*b3+32*b4); c3=32*b4; s=c0*B+cos(B)*(c1*sin(B)+c2*sin(B)*sin(B)*sin(B)+c3*sin(B)*sin(B)*sin(B)*sin(B)*sin(B)); x=s+(double)1/2*N*t*m*m+(double)1/24*(5-t*t+9*q2+4*q2*q2)*N*t*m*m*m*m+(double)1/720*(61-58*t*t+t*t*t*t)*N*t*m*m*m*m*m*m; y=N*m+(double)1/6*(1-t*t+q2)*N*m*m*m+(double)1/120*(5-18*t*t+t*t*t*t-14*q2-58*q2*t*t)*N*m*m*m*m*m; y=y+1000000*prjno+500000; pcc->x=x; pcc->y=y-38000000; ->z=0;}------解决方案--------------------
不懂c++的路过，楼主我没学过c++,临时看了些语法。。。要不是你找我，真不想趟这趟浑水。看能用不。。。
- Java code
public class CoordCovert { // 笛卡尔坐标系 class CRDCARTESIAN { double x; double y; double z; }; // 大地坐标系 class CRDGEODETIC { double longitude; // 经度 double latitude; // 纬度 double height; // 大地高,可设为0 } CRDGEODETIC PCRDGEODETIC = new CRDGEODETIC(); CRDCARTESIAN PCRDCARTESIAN = new CRDCARTESIAN(); void GeodeticToCartesian(CRDCARTESIAN pcc, CRDGEODETIC pcg, double dSemiMajorAxis, double dFlattening) { double B; //纬度度数 double L; //经度度数 double L0; //中央经线度数 double l; //L-L0 double t; //tanB double m; //ltanB double N; //卯酉圈曲率半径 double q2; double x; //高斯平面纵坐标 double y; //高斯平面横坐标 double s; //赤道至纬度B的经线弧长 double f = 0; //参考椭球体扁率 double e2; //椭球第一偏心率 double a = 0; //参考椭球体长半轴 //double b; //参考椭球体短半轴 double a1; double a2; double a3; double a4; double b1; double b2; double b3; double b4; double c0; double c1; double c2; double c3; //投影带号 int zonewide=3; int Datum=84; //投影基准面类型：北京54基准面为54，西安80基准面为80，WGS84基准面为84 int prjno=0; // double IPI=0.0174532925199433333333; //3.1415926535898/180.0 B = pcg.latitude ; //纬度 L = pcg.longitude ; //经度 if (zonewide==6) { prjno=(int)(L/zonewide)+1; L0=prjno*zonewide-3; } else { prjno=(int)((L-1.5)/3)+1; L0=prjno*3; } if(Datum==54) { a=6378245; f=1/298.3; } else if(Datum==84) { a=6378137; f=1/298.257223563; } L0=L0*IPI; L=L*IPI; B=B*IPI; e2=2*f-f*f;//(a*a-b*b)/(a*a); l=L-L0; t=tan(B); m=l * cos(B); N=a/sqrt(1-e2* sin(B) * sin(B)); q2=e2/(1-e2)* cos(B)* cos(B); a1=1+(double)3/4*e2+(double)45/64*e2*e2+(double)175/256*e2*e2*e2+(double)11025/16384*e2*e2*e2*e2+(double)43659/65536*e2*e2*e2*e2*e2; a2=(double)3/4*e2+(double)15/16*e2*e2+(double)525/512*e2*e2*e2+(double)2205/2048*e2*e2*e2*e2+(double)72765/65536*e2*e2*e2*e2*e2; a3=(double)15/64*e2*e2+(double)105/256*e2*e2*e2+(double)2205/4096*e2*e2*e2*e2+(double)10359/16384*e2*e2*e2*e2*e2; a4=(double)35/512*e2*e2*e2+(double)315/2048*e2*e2*e2*e2+(double)31185/13072*e2*e2*e2*e2*e2; b1=a1*a*(1-e2); b2=(double)-1/2*a2*a*(1-e2); b3=(double)1/4*a3*a*(1-e2); b4=(double)-1/6*a4*a*(1-e2); c0=b1; c1=2*b2+4*b3+6*b4; c2=-(8*b3+32*b4); c3=32*b4; s=c0*B+cos(B)*(c1*sin(B)+c2*sin(B)*sin(B)*sin(B)+c3*sin(B)*sin(B)*sin(B)*sin(B)*sin(B)); x=s+(double)1/2*N*t*m*m+(double)1/24*(5-t*t+9*q2+4*q2*q2)*N*t*m*m*m*m+(double)1/720*(61-58*t*t+t*t*t*t)*N*t*m*m*m*m*m*m; y=N*m+(double)1/6*(1-t*t+q2)*N*m*m*m+(double)1/120*(5-18*t*t+t*t*t*t-14*q2-58*q2*t*t)*N*m*m*m*m*m; y=y+1000000*prjno+500000; pcc.x = x; pcc.y = y-38000000; pcc.z = 0; } double sin(double args){ return Math.sin(args); } double cos(double args){ return Math.cos(args); } double sqrt(double args){ return Math.sqrt(args); } double tan(double args){ return Math.tan(args); }}