例如:
myBean[3].student[1].score[5].value
替换结果
myBean[4].student[2].score[6].value
其实就是把上面的[]里的数字+1替换。
原因我在使用
http://commons.apache.org/jxpath/
但里面index是开始是1,不是0.
------解决方案--------------------------------------------------------
这个试试
String str = "myBean[3].student[1].score[5].value";
Pattern pattern = Pattern.compile("\\[(\\d+)\\]");
Matcher matcher = pattern.matcher(str);
StringBuffer sb = new StringBuffer();
while(matcher.find()){
int value = Integer.parseInt(matcher.group(1));
matcher.appendReplacement(sb, String.valueOf(value + 1));
}
matcher.appendTail(sb);
System.out.println(sb.toString());
------解决方案--------------------------------------------------------
- Java code
public static void main(String[] args) { String str = "myBean[3].student[1].score[5].value"; Pattern pattern = Pattern.compile("\\[(\\d+)\\]"); Matcher m = pattern.matcher(str); while(m.find()){ str = str.replace(m.group(), "[" + (Integer.parseInt(m.group(1))+1) + "]"); } System.out.println(str); }