类的xml映射文件内容如下:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping
PUBLIC "-//Hibernate/Hibernate Mapping DTD 2.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-2.0.dtd">
<hibernate-mapping package="com.xxxx">
<class name="Customer" dynamic-insert="true" dynamic-update="true" table="CUSTOMERS">
<id name="id">
<generator class="increment"/>
</id>
<property name="name"/>
<property name="sex" access="field" />
<set name="orders" inverse="true" cascade="save-update">
<key column="CUSTOMER_ID" />
<one-to-many class="Order" />
</set>
<property name="description" type="string" column="DESCRIPTION"/>
</class>
</hibernate-mapping>
通过程序执行查询:
Session session = sessionFactory.openSession();
Transaction tx = null;
try {
tx = session.beginTransaction();
Customer customer=(Customer)session.load(Customer.class,new Long(customer_id));
tx.commit();
return customer;
}catch (Exception e) {
if (tx != null) {
// Something went wrong; discard all partial changes
tx.rollback();
}
throw e;
} finally {
// No matter what, close the session
session.close();
}
当执行到＂session.load＂时报错：
net.sf.hibernate.PropertyAccessException: Exception occurred inside setter of com.Customer.name
请问哪里的问题？
------解决方案--------------------
xml映射文件内容不对
------解决方案--------------------
检查com.xxxx
是否有public string setName方法
------解决方案--------------------
<class name="Customer" dynamic-insert="true" dynamic-update="true" table="CUSTOMERS">
<id name="id">
<generator class="increment"/>
</id>
<property name="name"/>
<property name="sex" access="field" />
这里映射没有标出id 没有和表里具体字段关联,
name 也没有和表里具体字段关联.
异常说的是Customer类里面没有public void setName(String name)方法,方法名严格区分大小写的