- XML code
<?xml version="1.0" encoding="UTF-8"?><users> <user> <id>1</id> <username>admin</username> <userpass>123456</userpass> </user> <user> <id>2</id> <username>zhang</username> <userpass>123456</userpass> </user></users>
自己写的xml
然后想在登录页面登录时候查询xml，看xml中有没有这个user对象，有就返回user对象
怎么弄啊。。。。
给点思路，网上搜的查询代码貌似都不行
------解决方案--------------------
ArrayList<User> list = new ArrayList<User>();
List<Element> idList = doc.selectNodes("//users/user/id");
List<Element> nameList = doc.selectNodes("//users/user/username");
List<Element> passwordList = doc.selectNodes("//users/user/userpass");
int count = idList.size();
for (int i = 0; i < count; i++) {
Element id = idList.get(i);
Element name = nameList.get(i);
Element password = passwordList.get(i);
User user = new User (id.getText());
user .setName(name.getText());
user .setPassword(password.getText());
list.add(user);
}
然后你再把list循环一遍，就知道有没有你的user了。。。。
------解决方案--------------------
- Java code
import java.io.*;import java.util.*;import org.w3c.dom.*;import javax.xml.parsers.*;public class D { public static void main(String arge[]) { long lasting = System.currentTimeMillis(); try { File f = new File("D://test.xml"); DocumentBuilderFactory factory = DocumentBuilderFactory .newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); Document doc = builder.parse(f); NodeList nl = doc.getElementsByTagName("user"); for (int i = 0; i < nl.getLength(); i++) { System.out.print("ID:" + doc.getElementsByTagName("id").item(i).getFirstChild().getNodeValue()); System.out.println("username:" + doc.getElementsByTagName("username").item(i).getFirstChild().getNodeValue()); System.out.println("userpass:" + doc.getElementsByTagName("userpass").item(i).getFirstChild().getNodeValue()); } } catch (Exception e) { e.printStackTrace(); } }}