JQUERY POST（）方法传参后台获取有关问题

function showMen(id ,branch,wherestation){                       var params = {"wherestation2":wherestation,"branch2":branch};                           // alert(params)          //document.write(params.wherestation2);             //document.write(params.branch2);         $.post("ajaxRequest.action",params,function(html){                //alert(html);                $("#men"+id).html(html);        });        }