【Java EE】Struts2.1.6与Spring2.5.6框架调整_J2EE

【Java EE】Struts2.1.6与Spring2.5.6框架整合

1、在MyEclipse中新建项目（test）
2、Struts包导入
???暂时导入所必需的包，其他包将在用到时导入：
???commons-fileupload-1.2.1.jar
???commons-logging-1.0.4.jar
???freemarker-2.3.13.jar
???ognl-2.6.11.jar
???struts2-core-2.1.6.jar
???xwork-2.1.2.jar
?3、复制在Struts目录的例子程序中WEB-INF\classes\struts.xml文件，粘贴到项目的src目录下，主要保留其文件头：

<?xml?version="1.0"?encoding="GBK"??>
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<!DOCTYPE?struts?PUBLIC
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????"-//Apache?Software?Foundation//DTD?Struts?Configuration?2.0//EN"
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????"http://struts.apache.org/dtds/struts-2.0.dtd">
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<struts>
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????<package?name="struts2"?extends="struts-default">
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????</package>
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</struts>

4、配置web.xml

<?xml?version="1.0"?encoding="UTF-8"?>
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<web-app?version="2.5"?xmlns="http://java.sun.com/xml/ns/javaee"
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????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
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????xsi:schemaLocation="http://java.sun.com/xml/ns/javaee?
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????http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
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????<filter>
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????????<filter-name>struts2</filter-name>
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????????<filter-class>
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????????????org.apache.struts2.dispatcher.FilterDispatcher
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????????</filter-class>
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????</filter>
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????<filter-mapping>
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????????<filter-name>struts2</filter-name>
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????????<url-pattern>/*</url-pattern>
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????</filter-mapping>
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????<welcome-file-list>
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????????<welcome-file>index.jsp</welcome-file>
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????</welcome-file-list>
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</web-app>

5、引入Spring包，在dist目录下
???spring.jar
6、在src目录下建立三个文件
???applicationContext-actions.xml
???applicationContext-beans.xml
???applicationContext-common.xml
???这三个文件其实是applicationContext.xml的分解，为的是避免所有配置放在同一文件，造成混乱。
???结构均如下：

<?xml?version="1.0"?encoding="GBK"?>
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<beans?xmlns="http://www.springframework.org/schema/beans"
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????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
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????xmlns:context="http://www.springframework.org/schema/context"
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????xmlns:tx="http://www.springframework.org/schema/tx"
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????xmlns:aop="http://www.springframework.org/schema/aop"
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????xsi:schemaLocation="http://www.springframework.org/schema/beans?http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
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????????????????http://www.springframework.org/schema/context?http://www.springframework.org/schema/context/spring-context-2.5.xsd
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????????????????http://www.springframework.org/schema/tx?http://www.springframework.org/schema/tx/spring-tx-2.5.xsd?
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????????????????http://www.springframework.org/schema/aop?http://www.springframework.org/schema/aop/spring-aop-2.5.xsd">
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</beans>

7、需要在web.xml进行配置

????<context-param>

????????<param-name>contextConfigLocation</param-name>

????????<param-value>classpath*:applicationContext-*.xml</param-value>

????</context-param>

????<listener>

????????<listener-class>

????????????org.springframework.web.context.ContextLoaderListener

????????</listener-class>

????</listener>

???前一段代码的配置是因为我们配置了后一段代码的配置后它默认是到WEB-INF下查找applicationContext.xml文件，我们现在改到src目录下并进行文件分解。

8、需要引入Struts2中的另一个包
???struts2-spring-plugin-2.1.6.jar
9、测试是否整合成功
（1）建立页面login.jsp、welcome.jsp、error.jsp分别为登录页面、登录成功页面、出错页面
login.jsp

<%@?page?language="java"?contentType="text/html;?charset=GB18030"
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????pageEncoding="GB18030"%>
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<%@?taglib?prefix="s"?uri="/struts-tags"%>
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<!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">
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<html>
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????<head>
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????????<meta?http-equiv="Content-Type"?content="text/html;?charset=GB18030">
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????????<title>登录页面</title>
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????</head>
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????<body>
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????????<s:form?action="login"?method="post">
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????????????<s:textfield?name="username"?label="username"?/>
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????????????<s:password?name="password"?label="password"?/>
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????????????<s:submit?value="submit"?/>
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????????</s:form>
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????</body>
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</html>

welcome.jsp

<%@?page?language="java"?contentType="text/html;?charset=GB18030"
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????pageEncoding="GB18030"%>
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<!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">
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<html>
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????<head>
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????????<meta?http-equiv="Content-Type"?content="text/html;?charset=GB18030">
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????????<title>登录成功</title>
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????</head>
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????<body>
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????????用户名：${username?}
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????????<br>
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????????密码：${password?}
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????????<br>
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????</body>
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</html>

（2）建包com.test.manager和com.test.manager.impl分别存放业务逻辑处理的接口和其实现，分别建立接口LoginManager.java和其实现LoginManagerImpl.java
LoginManager.java

package?com.test.manager;
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public?interface?LoginManager?{
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????public?boolean?isLogin(String?username,?String?password);
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}

LoginManagerImpl.java，只是测试用，判断用户名密码是否为intrl、intrl，若是则登录成功

package?com.test.manager.impl;
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import?com.test.manager.LoginManager;
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public?class?LoginManagerImpl?implements?LoginManager{
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????public?boolean?isLogin(String?username,?String?password)
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????{
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????????if(null!=username&&null!=password&&"intrl".equals(username.trim())&&"intrl".equals(password.trim()))
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????????{
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????????????return?true;
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????????}
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????????return?false;
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????}
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}

（3）在applicationContext-beans.xml把实现类配置上，以让Spring进行管理

????<bean?id="loginManager"

????????class="com.test.manager.impl.LoginManagerImpl">

????</bean>

（4）创建包com.test.action用于存放action，并新建LoginAction.java，继承ActionSupport类
包含从页面所接收参数username、password，以及业务逻辑处理类LoginManager类型的loginManager，给username和password设置get、set，给loginManager设置set方法，以让Spring为我们自动注入；overwrite父类中的

package?com.test.action;
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import?com.opensymphony.xwork2.ActionSupport;
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import?com.test.manager.LoginManager;
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@SuppressWarnings("serial")
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public?class?LoginAction?extends?ActionSupport?{
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????private?LoginManager?loginManager;
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????private?String?username;
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????private?String?password;
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????public?String?getUsername()?{
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????????return?username;
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????}
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????public?void?setUsername(String?username)?{
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????????this.username?=?username;
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????}
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????public?String?getPassword()?{
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????????return?password;
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????}
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????public?void?setPassword(String?password)?{
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????????this.password?=?password;
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????}
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