hibernate4 使用getCurrentSession().createQuery报错

hibernate4 使用getCurrentSession().createQuery报错，求助

public List findByProperty(String propertyName, Object value) {
		log.debug("finding FmUser instance with property: " + propertyName
				+ ", value: " + value);
		try {
			String queryString = "from FmUser as model where model."
					+ propertyName + "= ?";
			Query queryObject = getCurrentSession().createQuery(queryString);
			queryObject.setParameter(0, value);
			return queryObject.list();
		} catch (RuntimeException re) {
			log.error("find by property name failed", re);
			throw re;
		}
	}

调试到“getCurrentSession().createQuery”报一个错误：
Source not found for FmUserDAO$$FastClassByCGLIB$$deecd5cd.invoke(int, Object, Object[]) line: not available
提示找不到FmUser，但我在com.fundclien.entity.FmUser是存在的，它的代码是：

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.persistence.UniqueConstraint;

/**
 * FmUser entity. @author MyEclipse Persistence Tools
 */
@Entity
@Table(name = "FM_USER", schema = "GF", uniqueConstraints = @UniqueConstraint(columnNames = "VC_USER_CODE"))
public class FmUser implements java.io.Serializable {
@Id
	@GeneratedValue
	@Column(name = "L_USER_ID", unique = true, nullable = false, precision = 10, scale = 0)
	public Long getLUserId() {
		return this.LUserId;
	}

	public void setLUserId(Long LUserId) {
		this.LUserId = LUserId;
	}

	@Column(name = "VC_USER_CODE", unique = true, nullable = false, length = 16)
	public String getVcUserCode() {
		return this.vcUserCode;
	}
}

下面是applicationContext.xml配置：

<?xml version="1.0" encoding="UTF-8"?>

<beans
	xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns:p="http://www.springframework.org/schema/p"
	xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd" xmlns:tx="http://www.springframework.org/schema/tx">
	
	<bean id="dataSource"
		class="org.apache.commons.dbcp.BasicDataSource">
		<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver"></property>
		<property name="url"
			value="jdbc:oracle:thin:@127.0.0.1:1521:orcl">
		</property>
		<property name="username" value="gf"></property>
		<property name="password" value="gf"></property>
	</bean>
	<bean id="sessionFactory"
		class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
		<property name="dataSource">
			<ref bean="dataSource" />
		</property>
		<property name="hibernateProperties">
			<props>
				<prop key="hibernate.dialect">
					org.hibernate.dialect.Oracle9Dialect
				</prop>
				<prop key="hbm2ddl.auto">update</prop>
    			<prop key="hibernate.show_sql">true</prop>
			</props>
		</property>
		<property name="annotatedClasses">
			<list>
				<value>com.fundclien.entity.FmUser</value>
			</list>
		</property>
	</bean>
	<bean id="transactionManager"
		class="org.springframework.orm.hibernate4.HibernateTransactionManager">
		<property name="sessionFactory" ref="sessionFactory" />
	</bean>
	<tx:annotation-driven transaction-manager="transactionManager" />
	
	<bean
		id="fmUserDao" class="com.fundclien.dao.FmUserDAO">
		<property name="sessionFactory">
			<ref bean="sessionFactory" />
		</property>
	</bean>
	<bean id="login" class="com.fundclient.actions.loginAction">    
        <property name="fmUserDao" ref="fmUserDao" />
            </bean>  
            
</beans>

求前辈帮我看看是怎么回事啊？我调用FmUser instance = (FmUser) getCurrentSession().get("com.fundclien.entity.FmUser", id);则可以取得。
------解决方案--------------------
如果你喜欢注解，把seesionFactory中的属性 
<property name="annotatedClasses">
            <list>
                <value>com.fundclien.entity.FmUser</value>