使用struts+spring+hibernate时，action没法取得前台输入的值

使用struts+spring+hibernate时，action无法取得前台输入的值

求大神帮忙看看。密码能正确的传值，而用户名一直是null，而且把<s:password>也就是密码框这一句给删了之后用户名却能正确的传值了
login.jsp  

<s:form action="login.action" method="post">
        <s:textfield name="users.usrname"  label="用户名" size="21"/>
        <s:password name="users.usrpass" label="密码" size="21"/>
        <s:submit value="登陆"/>
    </s:form>

UserAction.java

public class UserAction extends ActionSupport{
    private UserService userService;
    private Users users;
    private Users getUsers(){
        return users;
    }
    public void setUsers(Users users){
        this.users=users;
    }
    public UserService getUserService(){
        return userService;
    }
    public void setUserService(UserService userService){
        this.userService=userService;
    }
    public String execute() throws Exception{
        System.out.println("用户名:"+users.getUsrname());//这里显示获得的usrname值是空的，但是usrpass值是对的，而且删了jsp里的usrpass输入框之后usrname就能正确传值
        Users yh =userService.find(users.getUsrname(),users.getUsrpass());
        if(yh!=null){
            Map session=(Map)ActionContext.getContext().getSession();
            session.put("users", yh);
            return SUCCESS;
        }
        else{
            System.out.print("wocao");
            return ERROR;
        }
            
    }

}

Users.java

public class Users implements java.io.Serializable {

	// Fields

	private String usrname;
	private String usrpass;
	private Userinfo userinfo;

	// Constructors

	/** default constructor */
	public Users() {
	}

	/** full constructor */
	public Users(String usrname, String usrpass) {
		this.usrname = usrname;
		this.usrpass = usrpass;
	}

	// Property accessors

	public String getUsrname() {
		return this.usrname;
	}

	public void setUsrname(String usrname) {
		this.usrname = usrname;
	}

	public String getUsrpass() {
		return this.usrpass;
	}

	public void setUsrpass(String usrpass) {
		this.usrpass = usrpass;
	}
	public Userinfo getUserinfo(){
		return this.userinfo;
	}
	public void setUserinfo(Userinfo userinfo){
		this.userinfo=userinfo;
	}

}

Users.hbm.xml

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- 
    Mapping file autogenerated by MyEclipse Persistence Tools
-->
<hibernate-mapping>
    <class name="org.model.Users" table="USERS" schema="dbo" catalog="KFGL">
        <id name="usrname" type="java.lang.String">
            <column name="usrname" length="10" />
            <generator class="foreign">
            	<param name="property">userinfo</param>
            </generator>
        </id>
        <property name="usrpass" type="java.lang.String">
            <column name="usrpass" length="10" not-null="true" />
        </property>
        <one-to-one name="userinfo" class="org.model.Userinfo" constrained="true"></one-to-one>
        
    </class>
</hibernate-mapping>

------解决思路----------------------

引用:

Quote: 引用:

是不是在传递password时setUsers方法把name清空了？为什么不在action中分开接收name和pass呢。

在action中分开接收name和pass是什么意思呢？在Users yh =userService.find(users.getUsrname(),users.getUsrpass());
这一句之前，我用System.out.println("用户名:"+users.getUsrname());显示取得的name，但是这里也是显示null

看起来像参数没获取过来，我只是觉得两个参数同时存储会不会互相影响，分开操作会不会成功，像这样：

public class UserAction extends ActionSupport{
    private UserService userService;
    private String username;
    private String password;
   
    //username, password 的getter, setter

    public UserService getUserService(){
        return userService;
    }
    public void setUserService(UserService userService){
        this.userService=userService;
    }
    public String execute() throws Exception{
        System.out.println("用户名:"+username);
        Users yh =userService.find(username,password);
        if(yh!=null){
            Map session=(Map)ActionContext.getContext().getSession();
            session.put("users", yh);
            return SUCCESS;
        }
        else{
            System.out.print("wocao");
            return ERROR;
        }
             
    }
 
}