当前位置: 代码迷 >> Exchange >> JAVA5线程并发库[八]-Exchanger(转)
  详细解决方案

JAVA5线程并发库[八]-Exchanger(转)

热度:7543   发布时间:2013-02-26 00:00:00.0
JAVA5线程并发库[8]-Exchanger(转)

??? 用于实现两个线程之间的数据交换,每个人在完成一定的事务后想与对方交换数据,第一个先拿出数据的人要一直等待第二个人拿着数据到来时,才能彼此交换数据

???

import java.util.concurrent.Exchanger;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
?
public class ExchangerTest {
?
????public static void main(String[] args) {
????????ExecutorService service = Executors.newCachedThreadPool();
????????final Exchanger<String> exchanger = new Exchanger<String>();
????????service.execute(new Runnable() {
????????????public void run() {
????????????????try {
?
????????????????????String data1 = "MacBook Pro";
????????????????????System.out.println("线程" + Thread.currentThread().getName()
????????????????????????????+ "正在把数据" + data1 + "换出去");
????????????????????Thread.sleep((long) (Math.random() * 10000));
????????????????????String data2 = (String) exchanger.exchange(data1);
????????????????????System.out.println("线程" + Thread.currentThread().getName()
????????????????????????????+ "换回的数据为" + data2);
????????????????} catch (Exception e) {
?
????????????????}
????????????}
????????});
????????service.execute(new Runnable() {
????????????public void run() {
????????????????try {
?
????????????????????String data1 = "8000RMB";
????????????????????System.out.println("线程" + Thread.currentThread().getName()
????????????????????????????+ "正在把数据" + data1 + "换出去");
????????????????????Thread.sleep((long) (Math.random() * 10000));
????????????????????String data2 = (String) exchanger.exchange(data1);
????????????????????System.out.println("线程" + Thread.currentThread().getName()
????????????????????????????+ "换回的数据为" + data2);
????????????????} catch (Exception e) {
?
????????????????}
????????????}
????????});
????????service.shutdown();
????}
}

上面讲到这些看上去意义不大,其实新技术就是这个样子,你没有遇到新技术善于解决的需求,所以没有看到它的价值,不过说不定下个月,老板的需求就让你抓耳挠腮了,那个时候说不定就是这些新技术大显身手的时候

?

?

?

转自:http://blog.onede4.com/java5-thread-concurrent-exchanger/