各位大侠，我现在想请教各位一个关于数组合并的问题，现在又两个数组
data={"[aaa,a1]","[bbb,b1]","[ccc,c1]"};
atomarr={"[aaa,5]","[bbb,4]","[ccc,6]"};
想将他们合并成一个数组，
data1={"[aaa,a1,5]","[bbb,b1,4]","[ccc,c1,6]"};
还请各位大侠将方法告诉我，谢谢各位大侠
------解决方案--------------------
遍历data，
{
解析data，
遍历atomarr，
{
解析atomarr，
比较
{ 合并 }
}
}
------解决方案--------------------
用一个数组把这两个数组的元素都复制到这个数组中
String[] data={"[aaa,a1]","[bbb,b1]","[ccc,c1]"};
String[] atomarr={"[aaa,5]","[bbb,4]","[ccc,6]"};
String[] total=new String[data.length+atomarr.length];
System.arraycopy(data, 0, total, 0, data.length);
System.arraycopy(atomarr, 0, total, 0+data.length, atomarr.length);
System.out.println(Arrays.toString(total));
------解决方案--------------------
String[] data=new String[]{"[aaa,a1]","[bbb,b1]","[ccc,c1]"};
String[] newDate=new String[]{"[aaa,5]","[bbb,4]","[ccc,6]"};
for(int i=0;i<data.length;i++){
String value=data[i];
String s=value.substring(1, value.length()-1);
String[] one=s.split(",");
for(int j=0;j<one.length;j++){
for(int m=0;m<newDate.length;m++){
String mValue=newDate[m];
String ms=mValue.substring(1, mValue.length()-1);
//System.out.println(ms);
String[] two=ms.split(",");
//System.out.println(two.length);
for(int n=0;n<two.length;n++){
if(one[j].equals(two[n])){
data[i]=value.substring(0,value.length()-1)+","+two[two.length-1]+"]";
break;
}
}
}
}
}
for(int o=0;o<data.length;o++){
System.out.println(data[o]);
}
------解决方案--------------------
public static void main(String[] args) {
// TODO Auto-generated method stub
String arr[]=new String[]{"[aaa,a1]","[bbb,b1]","[ccc,c1]"};
String array[]=new String[]{"[aaa,5]","[bbb,4]","[ccc,6]"};
List<String> list = new ArrayList<String>();
for(int i=0;i<arr.length;i++)
{
list.add(arr[i]);
}
for(int i=0;i<array.length;i++)
{
list.add(array[i]);
}
for(String a:list)
{
System.out.print(a);
}
}