看看函数的实参形参如何传递吧
----------------解决方案--------------------------------------------------------
int array[] = { 1, 2, 3, 4, 5 };
sizeof( array )是20
sizeof( array[0] )是4
int array[] = { 1, 2, 3, 4, 5 };
int *p=array;
sizeof(p)是4
----------------解决方案--------------------------------------------------------
----------------解决方案--------------------------------------------------------
int array[] = { 1, 2, 3, 4, 5 };
sizeof( array )是20
sizeof( array[0] )是4
int array[] = { 1, 2, 3, 4, 5 };
int *p=array;
sizeof(p)是4
----------------解决方案--------------------------------------------------------