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求goto的用法

热度:415   发布时间:2007-03-23 23:47:23.0
求goto的用法
struct student *del(struct student *head,long num)
{struct student *p1,*p2;
if(head==null)
{printf("\nlist null!\n");goto end;}
p1=head;
while(num!=p1->num&&p1->next!==null)
{p2=p1;p1=p1->next;}
if(num==p1->num)
{if(p1==head)head=p1->next;
else p2->next=p1->next;
printf("delete:%ld\n",num);
n=n-1;
}
else printf("%ld not beeb found!\n",num);
return(head);
}
这个函数在调试的时候说"Undefined label 'end' in function del"是什么回事啊?
该有goto end 是怎么用的啊?后面要不要加个结束的东西啊?
搜索更多相关的解决方案: goto  用法  

----------------解决方案--------------------------------------------------------
struct student *del(struct student *head,long num)
{struct student *p1,*p2;
if(head==null)
{printf("\nlist null!\n");goto end;}
p1=head;
while(num!=p1->num&&p1->next!==null)
{p2=p1;p1=p1->next;}
if(num==p1->num)
{if(p1==head)head=p1->next;
else p2->next=p1->next;
printf("delete:%ld\n",num);
n=n-1;
}
else printf("%ld not beeb found!\n",num);
return(head);
end:return NULL;
}

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恩,我去试下 谢谢拉

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我程序运行后出现这样的东西...请问什么意思哦.
scanf:floating point formats not linked
Abnormal program termination


----------------解决方案--------------------------------------------------------
while(num!=p1->num&&p1->next!==null
----------------解决方案--------------------------------------------------------

不是那个问题 我改了的 还是一样的结果 不行的
我把这个程序都传上来 你们看下 是关于动态链表的建立,输出,删除,插入的
#include <malloc.h>
#define null 0
#define len sizeof(struct student)
struct student
{long num;
float score;
struct student *next;
};

int n;

struct student *creat(void)
{struct student *head;
struct student *p1,*p2;
n=0;
p1=p2=(struct student *)malloc(len);
scanf("%ld,%f",&p1->num,&p1->score);
head=null;
while(p1->num!=0)
{n=n+1;
if(n==1)head=p1;
else p2->next=p1;
p2=p1;
p1=(struct student *)malloc(len);
scanf("%ld,%f",&p1->num,&p1->score);
}
p2->next=null;
return(head);
}

void print(struct student *head)
{struct student *p;
printf("\nthese %d records are:\n",n);
p=head;
if(head!=null)
do
{printf("%ld%5.1f\n",p->num,p->score);
p=p->next;
}while(p!=null);
}


struct student *del(struct student *head,long num)
{struct student *p1,*p2;
if(head==null)
{printf("\nlist null!\n");goto end;}
p1=head;
while(num!=p1->num&&p1->next!=null)
{p2=p1;p1=p1->next;}
if(num==p1->num)
{if(p1==head)head=p1->next;
else p2->next=p1->next;
printf("delete:%ld\n",num);
n=n-1;
}
else printf("%ld not beeb found!\n",num);
return(head);
end:return null;
}


struct student *insert(struct student *head,struct student *stu)
{struct student *p0,*p1,*p2;
p1=head;
p0=stu;
if(head==null)
{head=p0;p0->next=null;}
else
{while((p0->num>p1->num)&&(p1->next!=null))
{p2=p1;
p1=p1->next;}
if(p0->num<=p1->num)
{if(head==p1)head=p0;
else p2->next=p0;
p0->next=p1;}
else
{ p1->next=p0;p0->next=null;}
}
n=n+1;
return(head);
}


main()
{struct student *head,*stu;
long del_num;
printf("input records:\n");
head=creat();
print(head);
printf("\ninput the deleted number:");
scanf("%ld",&del_num);
while(del_num!=0)
{head=del(head,del_num);
print(head);
printf("\ninput the deleted number:");
scanf("%ld",&del_num);
}
printf("\ninput the inserted record:");
stu=(struct student *)malloc(len);
scanf("%ld,%f",&stu->num,&stu->score);
while(stu->num!=0)
{head=insert(head,stu);
print(head);
printf("\ninput the record:");
stu=(struct student *)malloc(len);
scanf("%ld,%f",&stu->num,&stu->score);
}
}


----------------解决方案--------------------------------------------------------
struct student *creat(void)
{struct student *head;
...
return(head);
}

这里 head是auto 型变量,在函数结束时,
它的会被系统收回,这样处理,本人认为有一点问题,
----------------解决方案--------------------------------------------------------
void print(struct student *head)
{struct student *p;
printf("\nthese %d records are:\n",n);
p=head; /*p=head->next;*/
if(head!=null) /*if(p!=NULL) head 里面没有装数据不能输出数据*/
do
{printf("%ld%5.1f\n",p->num,p->score);
p=p->next;
}while(p!=null);
}

void main()
{
..
print(head);
..
}

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你这里有几个函数用到了head,
但它里面没有数据,你就当作它里面有数据.
这是很危险的.


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