assume cs:code
year segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987',1988',1989',1990','1991','1992'
db '1993','1994','1995'
year ends
sum segment
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
sum ends
staff segment
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
staff ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
code segment
start:mov ax,table
mov ds,ax
mov ax,year
mov ss,ax
mov sp,0
mov bx,0
mov cx,21
s0:pop [bx]
pop [bx+2]
add bx,10H
loop s0
mov ax,staff
mov ss,ax
mov sp,0
mov bx,0
mov cx,21
s1:pop [bx+10]
add bx,10H
loop s1
mov ax,sum
mov ss,ax
mov sp,0
mov cx,21
mov bx,0
s2:pop ax
pop dx
mov [bx+5],ax
mov [bx+7],dx
div word ptr [bx+10]
mov [bx+14],ax
add bx,10h
loop s2
mov ax,4c00h
int 21h
code ends
end start
------解决方案--------------------------------------------------------
这个啊，接着打回车就是了。或者来个分号再回车；或者编译时，直接在 asm 文件名后加个分号。