assume cs:code,ds:data,es:table
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11452,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
code segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov si,0
mov bx,0
mov di,0
mov bp,0
mov cx,21
s:mov ax,es:[bx]
mov ds:[si],ax
mov ax,es:[bx+2]
mov ds:[si+2],ax
mov ax,ds:[si+84]
mov dx,ds:[si+86]
mov es:[bx+5],ax
mov es:[bx+7],dx
div word ptr ds:[di+168]
mov es:[bx+0dH],ax
mov ax,ds:[di+168]
mov es:[bx+0aH],ax
add di,2
add si,4
add bx,16
loop s
mov ax,4c00h
int 21h
code ends
end start
汇编
------解决方案--------------------
没看明白到底想干什么,把 data 段里的数据组织到 table 段里?这样的话,要理清了数据从哪里传到哪里吧,比如一开始的
s:mov ax,es:[bx]这个,明显是反了啊,将数据从 table 传到 data 段了。
mov ds:[si],ax
mov ax,es:[bx+2]
mov ds:[si+2],ax