实验环境：intel x386
一。要求：将3000H单元开始置数为00H-0FH
SSTACK SEGMENT STACK DW 32 DUP(?)SSTACK ENDSCODE SEGMENT ASSUME CS:CODE, SS:SSTACKSTART: PUSH DS XOR AX, AX MOV DS, AX MOV SI, 3000H MOV CX, 16AA1: MOV [SI], AL INC SI INC AL LOOP AA1 ;CX == 0? NEXT():AA1 MOV AX, 4C00H ;AH = 4C STOP CUR, RETURN INT 21HCODE ENDS END START
二。要求：将3500H后8位置入3600H开始的8位
有两种解法
1.
SSTACK SEGMENT STACK DW 32 DUP(?)SSTACK ENDSCODE SEGMENT ASSUME CS:CODE, SS:SSTACKSTART: PUSH DS XOR AX, AX ;SET AX = 0000H MOV DS, AX CLD ;CLOSE INTERUPTE MOV SI, 3500H MOV BX, 3600H MOV CX, 8 ;FOR LOOPAA1: MOV AL, [SI] ;REP MOVSB ;DS:[SI] -> ES:[DI], SI+1, DI+1 MOV [BX], AL INC SI INC BX LOOP AA1 ;CX == 0 ? NEXT() : AA1 MOV AX, 4C00H INT 21HCODE ENDS END START
2.
SSTACK SEGMENT STACK DW 32 DUP(?)SSTACK ENDSCODE SEGMENT ASSUME CS:CODE, SS:SSTACKSTART: PUSH DS XOR AX, AX ;SET AX = 0000H MOV DS, AX CLD ;CLOSE INTERUPTE MOV ES, AX MOV SI, 3500H MOV DI, 3600H MOV CX, 8 ;FOR LOOP REP MOVSB ;DS:[SI] -> ES:[DI], SI+1, DI+1 MOV AX, 4C00H INT 21HCODE ENDS END START
三。要求：将数据段中的str1赋给str2
DATA SEGMENT STR1 DB 'ABCDEFGHIJKLN' COUNT EQU $-STR1 ;$的值表示count的偏移地址, 而str1是BUF所占用的字节数 STR2 DB COUNT DUP(0)DATA ENDSSSTACK SEGMENT STACK ;!!--DEF--!汇编程序发现这是堆栈段,执行的时候会直接使SSTACK -> SS DB 200H DUP(0)SSTACK ENDSCODE SEGMENT ASSUME DS:DATA, ES:DATA, SS:SSTACK, CS:CODE ;DATA(DATA SEGMENT) ;ES(EXTRA DATA SEGMENT) ;SSTACK -> SS(STACK SEGMENT) ;CODE -> CS(CODE SEGMENT)START: MOV AX, DATA MOV DS, AX MOV ES, AX LEA SI, STR1 LEA DI, STR2 MOV CX, COUNT CLD ;Direction Flag to 0 (0 -> DF)LP1: MOVSB ;DS:[SI] -> ES:[DI], SI++, DI++ DEC CX ; JNZ LP1 ;THREE SENTENCE == REP MOVESB, CX FOR COUNT MOV AH, 4CH ;MOV AX, 4C00H INT 21HCODE ENDS END START
二。要求：将3500H后8位置入3600H开始的8位
四。要求：使用DOS接口输出一段字符串
DATA SEGMENT MESSAGE DB 'please input your name!' , 0DH, 0AH, '$'DATA ENDSCODE SEGMENTSTART: MOV AH, 09H MOV DX, SEG MESSAGE MOV DS, DX MOV DX, OFFSET MESSAGE INT 21H ...CODE ENDS