如果用户不正常退出一直保留在名单上面，如何设置有效时间内自动删除不活动（或没正常退出）的在线用户名单？不知如何实现？实时刷新的文件代码如下：
<meta http-equiv= "refresh " content= "5 ">
<%
online=Application( "onlinelist ")
online=split(online, " ")
Response.Write " <script language=javascript> parent.f6.document.open(); "
Response.Write "var winbgcolor = parent.cbg();var winbgimage = parent.cbi(); "
Response.Write "parent.f6.document.writeln( " " <body bgcolor= " " + winbgcolor + " " background= " " + winbgimage + " " bgproperties=fixed > " "); "
Response.Write "parent.f6.document.writeln( " " <style type= 'text/css '> A:visited{TEXT-DECORATION: none;Color:#000000}A:active{TEXT-DECORATION: none;Color:#000000}A:hover{TEXT-DECORATION: underline;Color:#000000}A:link{text-decoration: none;Color:#000000}BODY{FONT-FAMILY: '宋体 '; FONT-SIZE: 12px;} </style> " "); "
if ubound(online)=-1 then
Response.Write "msg= ' <a href=javascript:parent.seluser(\ '大家\ '); target=f2> 大家 </a> <br> ';parent.f6.document.writeln( '当前在线( 0 )人 <br> '); "
else
Response.Write "msg= ' <a href=javascript:parent.seluser(\ '大家\ '); target=f2> 大家 </a> <br> ';parent.f6.document.writeln( '当前在线( "&ubound(online)& " )人 <br> '); "
end if
for i=lbound(online) to ubound(online)-1
Response.Write "msg=msg+ ' <a href=javascript:parent.seluser(\ ' "&online(i)& "\ '); target=f2> "&online(i)& " </a> <br> '; "
next
Response.Write "parent.f6.document.writeln(msg); "
Response.Write " </script> "
%>
登录时初始数组代码如下：
<%
tmpname=request( "username ")
if Application( "chat_line ")= " " then
Dim sd_init(50)
for i=1 to 48
sd_init(i)=0
next
sd_init(49)=1
sd_init(50)= "数组初化成功! "
Application( "chat_sd ")=sd_init
Application( "chat_line ")=1
Application( "onlinelist ")= " "
end if
if not isarray(session( "dv_user ")) then
dim dv_user(3)
dv_user(0)=tmpname
dv_user(1)=Application( "chat_line ")
dv_user(2)=now()
dv_user(3)=0
session( "dv_user ")=dv_user
else
dv_user=session( "dv_user ")
end if
if Instr(LCase(Application( "onlinelist ")),LCase(dv_user(0)& " "))=0 then
Application.lock
Application( "onlinelist ")=Application( "onlinelist ")&dv_user(0)& " "
Application.UnLock
if dv_user(3)=0 then
Application.lock
sd=Application( "chat_sd ")
line=int(Application( "chat_line "))
Application( "chat_line ")=line+1
Dim newsd(50)
j=1
for i=3 to 50 step 2
newsd(j)=sd(i)
newsd(j+1)=sd(i+1)
j=j+2
next