我想用ASP生成这样的XML
<tiltviewergallery>
<photos>
<photo imageurl="imgs/1.jpg" linkurl="http://www.google.com">
<title>Image 1</title>
<description>我爱你们,哈哈</description>
</photo>
<photo imageurl="imgs/2.jpg" linkurl="http://www.google.com">
<title>Image 2</title>
<description>非常好</description>
</photo>
</photos>
</tiltviewergallery>
应该怎么办呢,其中ASP是读取数据库的
------解决方案--------------------
- VBScript code
<% Set oDoc = CreateObject("Msxml2.DOMDocument") With oDoc .async = False .validateOnParse = False .preserveWhiteSpace = False .resolveExternals = False End With Set oRoot = oDoc.createElement("tiltviewergallery") Set oDoc.documentElement = oRoot Set oPhotos = oDoc.createElement("photos") Do While Not rs.EOF Set oPhoto = oDoc.createElement("photo") oPhoto.setAttribute "imageurl", "imgs/1.jpg" oPhoto.setAttribute "linkurl", "http://www.google.com" Set oNode = oDoc.createElement("title") oNode.text = "title" oPhoto.appendChild oNode Set oNode = oDoc.createElement("description") oNode.text = "description" oPhoto.appendChild oNode oPhotos.appendChild oPhoto rs.MoveNext Loop oRoot.appendChild oPhotos oDoc.scave "c:\xxx\xxx.xml" Response.ContentType = "text/xml" Response.Write oDoc.xml %>