如何将LIST对像导出EXCEL

/// 将一组对象导出成EXCEL         /// </summary>         /// <typeparam name="T">要导出对象的类型<peparam>         /// <param name="objList">一组对象</param>         /// <param name="FileName">导出后的文件名</param>         /// <param name="columnInfo">列名信息</param>         public static void ExExcel<T>(List<T> objList, string FileName, Dictionary<string, string> columnInfo)        {            var tp = objList.First().GetType().GetProperties();            if (columnInfo.Count == 0) { return; }            if (objList.Count == 0) { return; }            //生成EXCEL的HTML             string excelStr = "";            Type myType = objList[0].GetType();            //根据反射从传递进来的属性名信息得到要显示的属性             List<PropertyInfo> myPro = new List<PropertyInfo>();            foreach (string cName in columnInfo.Keys)            {                PropertyInfo p = myType.GetProperty(cName);                if (p != null)                {                    myPro.Add(p);                    excelStr += columnInfo[cName] + "\t";                }            }            //如果没有找到可用的属性则结束             if (myPro.Count == 0) { return; }            excelStr += "\n";            foreach (T obj in objList)            {                foreach (PropertyInfo p in myPro)                {                    if (tp.ToList().Exists(c => c.Name.ToLower() == p.Name.ToLower()))                    {                        object pv = p.GetValue(obj, null);                        pv = pv == null ? "-" : pv;                        excelStr += pv + "\t";                    }                }                excelStr += "\n";            }            //输出EXCEL             HttpResponse rs = System.Web.HttpContext.Current.Response;            rs.ContentEncoding = System.Text.Encoding.GetEncoding("GB2312");            rs.AppendHeader("Content-Disposition", "attachment;filename=" + FileName);            rs.ContentType = "applicationnd.ms-excel";            rs.Write(excelStr);            rs.End();        }