C#获取XML内节指名_ASP.NET

C#获取XML内节点名

XML code

<?xml version="1.0" standalone="yes"?><users>  <xs:schema id="users" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">    <xs:element name="users" msdata:IsDataSet="true" msdata:Locale="en-US">      <xs:complexType>        <xs:choice minOccurs="0" maxOccurs="unbounded">          <xs:element name="user"><!--这里是表名-->            <xs:complexType>              <xs:sequence>                <xs:element name="userName" type="xs:string" minOccurs="0" msdata:Ordinal="0" />                <xs:element name="userPass" type="xs:string" minOccurs="0" msdata:Ordinal="1" />              </xs:sequence>              <xs:attribute name="id" type="xs:int" />            </xs:complexType>          </xs:element>        </xs:choice>      </xs:complexType>    </xs:element>  </xs:schema></users>

比如上面这个怎么获取<xs:element name="user"> 下的三个name值 ID UserName UserPass到一个数组

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http://download.csdn.net/download/qiujialongjjj/4640825 C#基类，收藏下吧。你能用到的
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这种格式的xml没碰到过，不过我采用变通的办法，也可以解决：

C# code

        string s = File.ReadAllText(Server.MapPath("~/test.xml"));        string xmlStr = s.Replace("xs:", "");        XmlDocument xmlDoc = new XmlDocument();        xmlDoc.LoadXml(xmlStr);        XmlNodeList names = xmlDoc.SelectNodes(@"//element[@name='user']//*/@name");        foreach (XmlNode name in names)            Response.Write(name.Value + "<br/>");
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C# code            XmlDocument xDoc = new XmlDocument();            xDoc.Load("..\\..\\test2.xml");            XmlNamespaceManager xnm = new XmlNamespaceManager(xDoc.NameTable);            xnm.AddNamespace("xs", "http://www.w3.org/2001/XMLSchema");            XmlNodeList xNodes = xDoc.DocumentElement.SelectNodes("//*/xs:choice/xs:element/*//*[@name]", xnm);            foreach (XmlNode item in xNodes)            {                Console.WriteLine(item.Attributes["name"].Value);            }            //输出：            //userName            //userPass            //id