Android Spring Rest Client“交换”创建类（406不可接受）

您正在尝试直接获取子节点，而不是通过父节点。 默认情况下，Rest Template尝试将响应JSON数据转换为指定的类，如果您的情况不满意，将抛出错误。

这是员工班

import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonPropertyOrder({
"personName",
"personSurname",
"personNumber",
"personMobile",
"personId",
"personCompanyCode"
})
public class Employee {

@JsonProperty("personName")
private String personName;
@JsonProperty("personSurname")
private String personSurname;
@JsonProperty("personNumber")
private String personNumber;
@JsonProperty("personMobile")
private String personMobile;
@JsonProperty("personId")
private String personId;
@JsonProperty("personCompanyCode")
private String personCompanyCode;

@JsonProperty("personName")
public String getPersonName() {
return personName;
}

@JsonProperty("personName")
public void setPersonName(String personName) {
this.personName = personName;
}

@JsonProperty("personSurname")
public String getPersonSurname() {
return personSurname;
}

@JsonProperty("personSurname")
public void setPersonSurname(String personSurname) {
this.personSurname = personSurname;
}

@JsonProperty("personNumber")
public String getPersonNumber() {
return personNumber;
}

@JsonProperty("personNumber")
public void setPersonNumber(String personNumber) {
this.personNumber = personNumber;
}

@JsonProperty("personMobile")
public String getPersonMobile() {
return personMobile;
}

@JsonProperty("personMobile")
public void setPersonMobile(String personMobile) {
this.personMobile = personMobile;
}

@JsonProperty("personId")
public String getPersonId() {
return personId;
}

@JsonProperty("personId")
public void setPersonId(String personId) {
this.personId = personId;
}

@JsonProperty("personCompanyCode")
public String getPersonCompanyCode() {
return personCompanyCode;
}

@JsonProperty("personCompanyCode")
public void setPersonCompanyCode(String personCompanyCode) {
this.personCompanyCode = personCompanyCode;
}

}

这是包含您的JSON响应的父类

import java.util.List;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonPropertyOrder({
"employees",
"result",
"message"
})
public class EmployeeDataResponse {

@JsonProperty("employees")
private List<Employee> employees = null;
@JsonProperty("result")
private Boolean result;
@JsonProperty("message")
private String message;

@JsonProperty("employees")
public List<Employee> getEmployees() {
return employees;
}

@JsonProperty("employees")
public void setEmployees(List<Employee> employees) {
this.employees = employees;
}

@JsonProperty("result")
public Boolean getResult() {
return result;
}

@JsonProperty("result")
public void setResult(Boolean result) {
this.result = result;
}

@JsonProperty("message")
public String getMessage() {
return message;
}

@JsonProperty("message")
public void setMessage(String message) {
this.message = message;
}

}

在这种情况下，您的休息电话应如下

EmployeeDataResponse employeeDataResponse = restTemplate.exchange(targetUrl, HttpMethod.GET, requestEntity, EmployeeDataResponse.class);

让我知道您是否需要有关答案的说明。