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Android顶用Toast.cancel()方法优化toast内容的显示

热度:211   发布时间:2016-05-01 19:55:43.0
Android中用Toast.cancel()方法优化toast内容的显示
产品在测试过程中发现一个bug,就是测试人员不停的疯狂的点击某个按钮,触发了toast以后,toast内容会一直排着队的显示出来,不能很快的消失。这样可能会影响用户的使用。

看到Toast有一个cancel()方法:

void cancel()
Close the view if it's showing, or don't show it if it isn't showing yet.
做程序员的,基本一看api就知道,用这个可以取消上一个toast的显示,然后显示下一个,这样就能解决出现的问题。可是在测试的过程中,发现却没有想象中的那么简单,不信可以百度一下,很多很多人发现toast的cancel()方法不起作用。还是不讲具体过程,只讲结果吧。

我把toast做成了一个应用类,方便使用,大家可以直接用:



[java] view plaincopyprint?
package com.arui.framework.android.util; 
 
import android.content.Context; 
import android.os.Handler; 
import android.os.Looper; 
import android.widget.Toast; 
package com.arui.framework.android.util;

import android.content.Context;
import android.os.Handler;
import android.os.Looper;
import android.widget.Toast;
[java] view plaincopyprint?
/**   
* Toast util class.   
*    
* @author <a href="http://blog.csdn.net/arui319">http://blog.csdn.net/arui319</a>   
* @version 2011/11/30   
*    
*/  
public class ToastUtil { 
 
    private static Handler handler = new Handler(Looper.getMainLooper()); 
 
    private static Toast toast = null; 
     
    private static Object synObj = new Object(); 
 
    public static void showMessage(final Context act, final String msg) { 
        showMessage(act, msg, Toast.LENGTH_SHORT); 
    } 
 
    public static void showMessage(final Context act, final int msg) { 
        showMessage(act, msg, Toast.LENGTH_SHORT); 
    } 
 
    public static void showMessage(final Context act, final String msg, 
            final int len) { 
        new Thread(new Runnable() { 
            public void run() { 
                handler.post(new Runnable() { 
                    @Override 
                    public void run() { 
                        synchronized (synObj) { 
                            if (toast != null) { 
                                toast.cancel(); 
                                toast.setText(msg); 
                                toast.setDuration(len); 
                            } else { 
                                toast = Toast.makeText(act, msg, len); 
                            } 
                            toast.show(); 
                        } 
                    } 
                }); 
            } 
        }).start(); 
    } 
 
 
    public static void showMessage(final Context act, final int msg, 
            final int len) { 
        new Thread(new Runnable() { 
            public void run() { 
                handler.post(new Runnable() { 
                    @Override 
                    public void run() { 
                        synchronized (synObj) { 
                            if (toast != null) { 
                                toast.cancel(); 
                                toast.setText(msg); 
                                toast.setDuration(len); 
                            } else { 
                                toast = Toast.makeText(act, msg, len); 
                            } 
                            toast.show(); 
                        } 
                    } 
                }); 
            } 
        }).start(); 
    } 
 




代码的逻辑很简单。这里加了同步,这样做可以确保每一个toast的内容至少可以显示出来,而不是还没显示就取消掉了。这样做,是因为toast的内容不一定完全相同,如果没显示出来,也会有问题。






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GL(arui319)

http://blog.csdn.net/arui319
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