Android ListView兑现快速定位联系人功能【转发】

整合了Android ListView分组界面布局改进和java实现List中汉字字母混排序，实现了类似iOS那样的快速定位效果，如下图：

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主要是MainActivity实现了 OnTouchListener和OnGestureListener接口。

其中onScroll方法如下：

@Override
public boolean onScroll(MotionEvent e1, MotionEvent e2, float distanceX,
??????? float distanceY) {

??? util(e2);

??? return false;
}

util方法，根据手势位置，确定快速定位到那个字母：

public void util(MotionEvent e2) {
??? int i = (int) ((e2.getRawY() – view.getTop()) / ((float) view
??????????? .getHeight() / 26f));
??? int j=0;
??? switch (i) {
??? case 0:
??????? int pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);
??????? break;

??? case 1:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);
??????? break;

??? case 2:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);
??????? break;

??? case 3:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);
??????? break;

??? case 4:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);
??????? break;

??? case 5:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 6:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 7:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 8:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 9:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 10:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 11:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 12:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 13:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 14:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 15:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 16:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??? case 17:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 18:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 19:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??? case 20:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 21:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 22:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 23:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 24:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? case 25:
??????? pos = (myAdapter).getPositionForSection(j++);
??????? listView.setSelectionFromTop(pos, 0);

??????? break;

??? default:
??????? break;
??? }
}

这样就实现了随手势在右边区域滑动，listview快速定位。

快速滑动首字母提示参见：ListView快速滑动示例增加首字母提示。

源代码见：http://bigcateasymorse.googlecode.com/svn/trunk/android-listview-separate-demo0.5/

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