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View Android Source Code in Eclipse
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Recently, I have been hacking around with?Android?a lot, and I think it's awesome.
Unfortunately, the?Android SDK?does not come with source code, and sometimes the?docs?are not so great, yet. Being an open source project, the?Android sources?are available online, but they are not very easy to access from Eclipse. For one, the source files are sometimes difficult to find as they are distributed over many individual Gitrepositories, and then I am not always online.
Integrating source files into Eclipse is usually quite easy, but the Android Eclipse plugin (ADT) does not allow to modify the Java Source Attachment of android.jar in the Android Library. Fortunately, you only have to find out what the default location for source code is. Eric Burke nicely describes?how to find that out.
Long story short: Android source code needs to be placed in a "sources" subdirectory of the Android SDK. Here is what you need to do:
- Get the Android source code?(install repo, repo init, repo sync)
- Move all Java sources into a "sources" subdirectory of the Android SDK
Step 2 sounds easier than it is. There are a lot of Java files in the Android sources, and they are sprinkled all over the place. Eclipse, however, needs the source files in a standard Java source directory structure: The path of a source file needs to match its package name. To simplify this task, I have written a short Python script that recursively searches for Java files and packs them into a ZIP file. Unpack that source file into a "sources" subdirectory of the Android SDK. Enjoy:
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from __future__ import with_statement # for Python < 2.6import osimport reimport zipfile# open a zip fileDST_FILE = 'sources.zip'if os.path.exists(DST_FILE): print DST_FILE, "already exists" exit(1)zip = zipfile.ZipFile(DST_FILE, 'w', zipfile.ZIP_DEFLATED)# some files are duplicated, copy them only oncewritten = {}# iterate over all Java filesfor dir, subdirs, files in os.walk('.'): for file in files: if file.endswith('.java'): # search package name path = os.path.join(dir, file) with open(path) as f: for line in f: match = re.match(r'\s*package\s+([a-zA-Z0-9\._]+);', line) if match: # copy source into the zip file using the package as path zippath = match.group(1).replace('.', '/') + '/' + file if zippath not in written: written[zippath] = 1 zip.write(path, zippath) break; zip.close()??
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