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AudioTrack:getMinFrameCount代码懂得

热度:46   发布时间:2016-05-01 18:10:13.0
AudioTrack::getMinFrameCount代码理解?
Frame的大小是一个采样点的字节数 X 声道数。
那么,对于AudioTrack中取得最小buffer大小的函数,具体如何理解?
C/C++ code
static jint android_media_AudioTrack_get_min_buff_size(JNIEnv *env,  jobject thiz,    jint sampleRateInHertz, jint nbChannels, jint audioFormat) {    int frameCount = 0;    if (AudioTrack::getMinFrameCount(&frameCount, AudioSystem::DEFAULT,            sampleRateInHertz) != NO_ERROR) {        return -1;    }    return frameCount * nbChannels * (audioFormat == javaAudioTrackFields.PCM16 ? 2 : 1);// frameCount是如何计算的?}


取得frameCount的处理函数,难点是理解取得frameCount的处理
C/C++ code
status_t AudioTrack::getMinFrameCount(        int* frameCount,        int streamType,        uint32_t sampleRate){    int afSampleRate;    if (AudioSystem::getOutputSamplingRate(&afSampleRate, streamType) != NO_ERROR) {        return NO_INIT;    }    int afFrameCount;    if (AudioSystem::getOutputFrameCount(&afFrameCount, streamType) != NO_ERROR) {        return NO_INIT;    }    uint32_t afLatency;    if (AudioSystem::getOutputLatency(&afLatency, streamType) != NO_ERROR) {        return NO_INIT;    }    // Ensure that buffer depth covers at least audio hardware latency    uint32_t minBufCount = afLatency / ((1000 * afFrameCount) / afSampleRate); // 此计算公式如何理解?    if (minBufCount < 2) minBufCount = 2;    *frameCount = (sampleRate == 0) ? afFrameCount * minBufCount :              afFrameCount * minBufCount * sampleRate / afSampleRate; // 此公式又如何理解?    return NO_ERROR;}


以上该怎么理解?

------解决方案--------------------
这个我也想知道,不知道楼主现在得到答案了吗。